Unable to display the image path correctly from php array

Question

Im trying to display the html like echo $contentsArray[0]; in php, however the image is not displayed. since, the img path is displayed like "<?=POST_IMG?>post/item/mypost/post_1.png" instead of "img/PostImg/post/item/mypost/post_1.png". How should I fix this problem.

define('POST_IMG', 'img/PostImg/');

$item1 = '<a href="#" target="_blank"> <div class="left">
              <img src="<?=POST_IMG?>post/item/mypost/post_1.png">
            </div></a>';

$contentsArray = array($item1, ...More

Its a string to php so do like this <img src="'.POST_IMG.'post/item/mypost/post_1.png">. You just have to concatinate the variable in your string — Aman Rawat
– Aman Rawat, Commented May 8, 2017 at 5:29

Nitin Pund · Accepted Answer · 2017-05-08 05:36:59Z

1

Well you have problem with the concatenation inside your code. you can refer following code,

Note : it is better to avoid use of short-hand php tag

 define('POST_IMG', 'img/PostImg/');

$contentsArray = array('<a href="#" target="_blank">
        <div class="left">
           <img src= "'.POST_IMG.'post/item/mypost/post_1.png">
        </div>
</a>', ...More

answered May 8, 2017 at 5:36

Nitin Pund

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