"Array subscript is not an integer" in C program

Question

void imprimirTablero(char *tablero[7][7], int *posicionX, int *posicionY)
{
    int i, j;
    tablero[posicionX][posicionY] = 'R';
    for(i = 0; i < LEN(tablero); i++)
    {
        for(j = 0; j < LEN(tablero[0]); j++)
        {
            printf(tablero[i][j]);
        }
    }
}

this method change the char in positionX, positionY and print the new matrix of chars.... please someone help me

dbush · Accepted Answer · 2017-05-22 02:10:37Z

1

You're using a pointer to an integer as an array index for both posicionX and posicionY. You need to dereference those pointers:

tablero[*posicionX][*posicionY] = 'R';

answered May 22, 2017 at 2:10

dbush

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4 Comments

L. Scott Johnson Over a year ago

or more likely, change them to int instead of int pointers void imprimirTablero(char *tablero[7][7], int posicionX, int posicionY)

VolAnd Over a year ago

L. Scott Johnson gave a good advice: if there is no needs to changeposicionX and posicionY, they must be passed as simple int value (by value)

L. Scott Johnson Over a year ago

Right. Your advice was good and correct. And there was no "need" to do it without pointers. But it is more likely that the core mistake was using pointers in the first place, not just in the forgetting to dereference them.

L. Scott Johnson Over a year ago

@VolAnd: and note the assignment of a char to the char pointer on that same line: another indication that the programmer is just confused about the parameter specification format.

L. Scott Johnson · Accepted Answer · 2017-05-22 02:19:10Z

1

You're passing a 2D array of pointers, not chars, and two pointers to ints, not ints. I think you want:

void imprimirTablero(char tablero[7][7], int posicionX, int posicionY)

judging by

tablero[posicionX][posicionY] = 'R';

answered May 22, 2017 at 2:19

L. Scott Johnson

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