python restart the program after running a method

Question

A noob question I'm sure. For example, say I have a program that looks something like this.

def method1():
    #do something here

def method2():
    #do something here

#this is the menu
menu=input("What would you like to do?\ntype 1 for method1 or 2 for method2: ")
if(menu=="1"):
    method1()
if(menu=="2"):
    method2()

How can I make this menu appear again after a method has finished instead of the program terminating?

I was thinking I could wrap the whole program into an endless loop, but that doesn't feel right :P

I'd do it with an endless loop (or not endless, depending on whatever else you're doing). — rovaughn
– rovaughn, Commented Dec 10, 2010 at 22:19
Wrap it non-endless loop were there is choice to exit the program. — nate c
– nate c, Commented Dec 10, 2010 at 22:19

Russell Borogove · Accepted Answer · 2010-12-10 22:22:17Z

5

while True:
    #this is the menu
    menu=input("What would you like to do?\ntype 1 for method1 or 2 for method2: ")
    if(menu=="1"):
        method1()
    if(menu=="2"):
        method2()

If the endless loop "doesn't feel right", ask yourself when and why it should end. Should you have a third input option that exits the loop? Then add:

if menu == "3":
    break

answered Dec 10, 2010 at 22:22

Russell Borogove

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2 Comments

Steinthor.palsson Over a year ago

thanks this is great. I was gonna put the whole thing inside the loop, methods and everything xD

Karl Knechtel Over a year ago

Well... you never really want to wrap "the whole program" in a loop; you want to wrap the part that needs to loop in a loop. :)

Pengman · Accepted Answer · 2010-12-10 22:24:29Z

0

An endless loop is the way to do it though, something like this:

running = true

def method1(): 
   #do something here

def method2():
    #do something here

def stop():
    running = false

while running:
    #this is the menu
    menu=input("What would you like to do?\ntype 1 for method1 or 2 for method2 (3 to stop): ")
    if(menu=="1"):
        method1()
    if(menu=="2"):
       method2()
    if(menu=="3"):
       stop()

answered Dec 10, 2010 at 22:24

Pengman

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1 Comment

Pengman Over a year ago

Russels method is better than this

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