How to effectively handle key error exception in python?

Question

I have a dictionary with certain items. I want to accept the key input from the user and display the corresponding item. However if the user enters the wrong key which is not defined in the dictionary, it throws key error exception.

I want the code to go back to the line end execute from where the command for user input is written if key error exception occurs.

I have used try except statements but shows an error. Please help me to fix this.

Below is my code:

a={'name':'pav','q1':'y','age':26}
try:
  k=input()
  print (a[k])
except KeyError: 
  continue

You need a (while or for) loop to continue. Are you? What exception, exactly? — jonrsharpe
– jonrsharpe, Commented May 27, 2017 at 10:25

Marco · Accepted Answer · 2017-05-27 10:44:12Z

1

there is a simpler way if you don't want to use a try and except

Simply use dict.get(key) if the key exists it returns its value otherwise it will return None and you can simply check that value:

key=input()
value = dict.get(key)

while value == None:
    key=input()
    value = dict.get(key)

print value

answered May 27, 2017 at 10:44

Marco

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user3029392 · Accepted Answer · 2017-05-27 12:36:19Z

0

This can be done in two ways, either by setting the number of try limits or with an infinite loop.

Below is an example for 3 try limits, for an infinite loop you can replace for loop with while.

a={'name':'pav','q1':'y','age':26}

for i in range(3):
       k = input()
       if k in a:
           print(a[k])
           break
       else:
           print('Please enter the valid value')

edited May 27, 2017 at 12:36

answered May 27, 2017 at 12:28

user3029392

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