javascript regex to exclude a pattern only if another pattern does not match

Question

A regex is needed in order to exclude sentences with wag[.|on] or ut[i|e] but only if NO sed[.|an] is present and allow all other sentences. any suggestions?
ie. exclude matches that are only wagon or only ute.

I tried /[^wag[on|.]]/ig.test(sentence) but this way will not allow exclusion. I need to select the "yes" sentences only as below.

Given the following sentences:
the sedan is fast <-- yes
other sed. is fast too <-- yes
the wagon is slow <-- no
other wag. is also slow <-- no
the ute is slow <-- no
other uti is also slow <-- no
the wag. and wagon slower then sed. or sedan <-- yes
the uti or ute is slower then sed. or sedan <-- yes
both wag. wagon and uti and ute are slow <-- no
nothing is fast or slow <-- yes

have you considered to use two regex for this? I don't think you can make it one. — Val
– Val, Commented Jun 2, 2017 at 3:44
could you give some solution as to how you could do it with 2 regex. thx — Fred J.
– Fred J., Commented Jun 2, 2017 at 3:56
do you mean wag[.|on] or wag(on)? or wag(.|on)? they are different. — tsh
– tsh, Commented Jun 2, 2017 at 5:19

Val · Accepted Answer · 2017-06-02 04:05:03Z

2

this does the trick

function isMatch(input) {
   var regno = /(wag[.|on]|ut[i|e])/gi;
   var regyes = /sed[.|an]/gi;
   return !regno.test(input) || regyes.test(input);
}

result:

answered Jun 2, 2017 at 4:05

Val

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tsh · Accepted Answer · 2017-06-02 05:21:26Z

0

/^(?:.*sed[.|an].*|(?:(?!wag[.|on]|ut[i|e]).)*)$/

you can use (?!) to match a string who do not match some pattern.

answered Jun 2, 2017 at 5:21

tsh

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