PHP: skipping a default parameter in a function call

Question

The below is a php function:

bool mkdir ( string $pathname [, int $mode = 0777 [, bool $recursive = false [, resource $context ]]] )

I would like to call the function, specifying the first and the third parameters, leaving the second default. Can I?

nico · Accepted Answer · 2014-08-26 18:39:46Z

8

No, you cannot. See http://www.php.net/manual/en/functions.arguments.php esp. ex #5 and #6

Specifically:

Note that when using default arguments, any defaults should be on the right side of any non-default arguments; otherwise, things will not work as expected.

edited Aug 26, 2014 at 18:39

answered Dec 15, 2010 at 19:11

nico

51.9k17 gold badges92 silver badges118 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

cjdaniel Over a year ago

For user defined functions and methods you can use Syntactic github.com/topclaudy/php-syntactic

activout.se · Accepted Answer · 2010-12-15 20:08:57Z

1

Make a wrapper function with only the parameters you want to specify.

answered Dec 15, 2010 at 20:08

activout.se

6,1164 gold badges30 silver badges37 bronze badges

Collectives™ on Stack Overflow

PHP: skipping a default parameter in a function call

2 Answers 2

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related