create an instance from type with multiple constructor in scala

Question

I have a class I created with 2 constructors.

I want to create an instance of this class using only default constructor.

class A (arg1:Int,Arg2:String){
   def this(arg1:Int){
      this(arg1,"hello")
   }
}

here is what I tries to do:

val tpe = ru.typeOf[A]
val mirror = ru.runtimeMirror(getClass.getClassLoader)
val clsSym = tpe.typeSymbol.asClass
val clsMirror = mirror.reflectClass(clsSym)
val ctorSym = tpe.decl(ru.termNames.CONSTRUCTOR).asMethod
val method = clsMirror.reflectConstructor(ctorSym)
val newInstance = method(args:_*)

I'm getting the following error:

constructor ExampleWithCamelCase encapsulates multiple overloaded
alternatives and cannot be treated as a method. Consider invoking 
<offending symbol>.asTerm.alternatives` and manually picking the required method

is there away to choose the default constructor?

chengpohi · Accepted Answer · 2017-06-16 04:54:32Z

1

classOf[A].getConstructors()(1).newInstance(1)

you can simply use the Java reflection to newInstance to initiate with multiple constructor.

answered Jun 16, 2017 at 4:54

chengpohi

14.2k1 gold badge28 silver badges43 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

create an instance from type with multiple constructor in scala

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related