Is it possible to get a fifth column with my current code ? Actually the output looks like that when I add the Column5:
Column1 : infra-1 Column2 : infra-852 Column3 : infra-12 Column4 : infra-99 Column5 : infra-25
The output without Column5:
Column1 Column2 Column3 Column4
------- ------- ------- -------
infra-1 infra-852 infra-12 infra-99
I use $csv | Select-Object Column1,Column2,Column3,Column4 to display it.