Call to a member function links() on array in Laravel

Question

I am receiving this error while trying to create pagination in laravel.

ErrorException in 1e886a45102a3e4898f23b52cd7ca771 line 396: Call to a member function links() on array (View: C:\xampp\htdocs\soulfy_repo\framework\resources\views\soulfy\setting.blade.php)

line 396:  <?php echo e($themes->links()); ?>

HomeController.php

public function getBackgroundTheme()
{

    $query = DB::table('theme_background');

    if (request()->has('menu')) {
        $theme = DB::table('kategori_name')->where('kategori_theme', request('menu'))->first();

        $query = $query->where('kategori_id', $theme->kategori_id);
    }

    //$model = $query->get();
    $theme = $query->paginate(4);

    return view('soulfy.setting', [
        'themes'=>$theme,
        'user' => auth()->user(),
    ]);


    // return redirect('/home/setting' . 
}

setting.blade.php

        <table>

    @if(isset($themes))
        @foreach($themes as $m)

            <tr>
                <td><img width="100px" height="100px" src="{{url('/')}}/uploads/theme/{{$m->pic_name}}.jpg"/></td>
                <td><img width="100px" height="100px" src="{{url('/')}}/uploads/theme/{{$m->pic_name}}.jpg"/></td>
                <td><img width="100px" height="100px" src="{{url('/')}}/uploads/theme/{{$m->pic_name}}.jpg"/></td>
            </tr>

            <tr>
                <td><div class="box"><input type="checkbox" name="pic" value=""></div></td>
                <td><input type="checkbox" name="pic" value=""></td>
                <td><input type="checkbox" name="pic" value=""></td>
            </tr>

        @endforeach

        {{ $themes->links() }}
    @endif


</table>

try to comment the if block : this one if (request()->has('menu')) { $theme = DB::table('kategori_name')->where('kategori_theme', request('menu'))->first(); $query = $query->where('kategori_id', $theme->kategori_id); } and see if it will work — Maraboc
– Maraboc, Commented Jul 17, 2017 at 8:33

Siva Ganesh · Accepted Answer · 2018-05-17 11:23:44Z

1

 $theme = DB::table('kategori_name')->where('kategori_theme', request('menu'))->paginate(PAGELIMIT);

Use This In Your Home Controller. Instead Of first(); And Define This In Your Routes : define('PAGELIMIT','4');

edited May 17, 2018 at 11:23

answered Jul 17, 2017 at 8:58

Siva Ganesh

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