Convert unsigned char array into uint8_t array?

Question

I need convert unsigned char array into unit8_t array maybe someone has an idea how to do it?

I tried to look for information on the Internet, but unfortunately I did not succeed.

:)

There's nothing to convert. Iff uint8_t exists, it is the same as unsigned char. Or the other way around: If unsigned char has more than 8 bits, there's no uint8_t available. — user2371524
– user2371524, Commented Jul 28, 2017 at 11:01

Mike Nakis · Accepted Answer · 2017-07-28 10:59:48Z

6

So, have you tried uint8_t* myuint8array = (uint8_t*)myuchararray; ?

answered Jul 28, 2017 at 10:59

Mike Nakis

63k11 gold badges128 silver badges173 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Robert · Accepted Answer · 2017-07-28 11:02:08Z

1

You have

unsigned char arr[size];

and you want

uint8_t arr[size];

uint8_t is simply defined as

typedef unsigned char uint8_t;

:-)

answered Jul 28, 2017 at 11:02

Robert

3172 silver badges16 bronze badges

9 Comments

user2371524 Over a year ago

Or not defined at all, in case char has more than 8 bits.

Robert Over a year ago

And when would a character possibly have more than 8 bits?

Bo Persson Over a year ago

@Robert - It could for example be 9 bits on a 36-bit computer.

user2371524 Over a year ago

character != char. And then, the answer is "when it has more than 8 bits". Yes, such platforms exist and they can't provide uint8_t for obvious reasons.

Robert Over a year ago

This was complete news to me, i have never heard of this before. Thanks, will read this straight away. :-)

|

Collectives™ on Stack Overflow

Convert unsigned char array into uint8_t array?

2 Answers 2

Comments

9 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

9 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related