Debugging php object instantiation

Question

I am using ajax to call a php script (wordpress). I get status code 200 OK but I dont get any data back.. My script dies, when trying to create an instant of an object. But I cant get any info why..

// create Order object
echo "this gets returned";
try {
   if(new Order($auth_login, $auth_password, $caleo_live_mode)) {
       echo "works";
    } else {
        echo "if error";
    }
} catch (Exception $e) {
    echo "try fail";
}
echo "This does not";

Nothing inside the try block is getting returned.

What can I do to try to see what is going on?

Bugs · Accepted Answer · 2017-08-14 12:52:56Z

1

Moved solution from question to answer:

ANSWER: I figured it out....

I read through the source code of Order and found a try/catch statement which looked like:
catch (Exception $e) {
    exit();
}

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