Remove empty nodes with no attributes from XML using XSLT

Question

Input XML:

 <?xml version="1.0" encoding="UTF-8"?>
<dataset>
<TEST ID="1" DATA="DATE"/>
<TEST/>
<TEST2 ID="3" COLUMN="VALUE"/>
</dataset>

Desired Output:

<?xml version="1.0" encoding="UTF-8"?>
<dataset>
<TEST ID="1" DATA="DATE"/>
<TEST2 ID="3" COLUMN="VALUE"/>
</dataset>

Current applied XSLT:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="*[not(child::node())]"/>
    <xsl:template match="node()|@*">
      <xsl:copy>
        <xsl:apply-templates select="node()|@*"/>
      </xsl:copy>
    </xsl:template>
</xsl:stylesheet>

Current Output:

<?xml version="1.0" encoding="UTF-8"?>
<dataset>
</dataset>

What could be the condition to be applied, to achieve output without empty '<TEST/>' node in result.

Ajeet Singh · Accepted Answer · 2017-08-24 12:10:15Z

3

Check following Code

<xsl:template match="node()|@*">
  <xsl:copy>
    <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
</xsl:template>

<xsl:template match="*[not(@*|*|comment()|processing-instruction()) and normalize-space()='']"/>

answered Aug 24, 2017 at 12:10

Ajeet Singh

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Comments

michael.hor257k · Accepted Answer · 2017-08-24 12:13:26Z

3

If you want to keep elements that have either child nodes or attributes, then change this:

<xsl:template match="*[not(child::node())]"/>

to:

<xsl:template match="*[not(node() or @*)]"/>

Note that child is the default axis, so child:: can be omitted.

answered Aug 24, 2017 at 12:13

michael.hor257k

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