Get Min() Value From Int Array

Question

I am creating an int array by using the below syntax

int start = Math.Min(Convert.ToInt32(FirstNum), Convert.ToInt32(SecondNum));
int end = Math.Max(Convert.ToInt32(FirstNum), Convert.ToInt32(SecondNum));
end = end + 1;
int[] ang = Enumerable.Range(start, end - start).ToArray();
foreach (int a in ang) {int first = a.Min(); }

However I have a compile error of

'int' does not contain a definition for 'Min' and the best extension method overload 'Enumerable.Min(IEnumerable)' requires a receiver of type 'IEnumerable'

What is the proper way to get the MIN() value from the array of ints?

@Vanna - good catch! I am needing to check the array not the individual item from the array. I also need to set it to int first == a.Min(); — Yohan Greenburg
– Yohan Greenburg, Commented Aug 27, 2017 at 23:18
You do not need the loop. Use just int first = ang.Min(); and get rid of the loop. — Code-Apprentice
– Code-Apprentice, Commented Aug 27, 2017 at 23:26
Since the elements are already in ascending order, ang[0] is the minimum element. — Code-Apprentice
– Code-Apprentice, Commented Aug 27, 2017 at 23:28

Connor · Accepted Answer · 2017-08-28 00:13:15Z

1

int start = Math.Min(Convert.ToInt32(FirstNum), Convert.ToInt32(SecondNum));
int end = Math.Max(Convert.ToInt32(FirstNum), Convert.ToInt32(SecondNum));
end = end + 1;
int[] ang = Enumerable.Range(start, end - start).ToArray();

var minimumValue = ang.Min();

answered Aug 28, 2017 at 0:13

Connor

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