Complex Python Regex for Django View

Question

URL structure look liks this: <domain>/<version>/<collection>/<sub-collection>/<page> where domain is anything a-zA-Z0-9\-\_, version is anything a-zA-Z0-9\-\_\. (But would likely be only 1.0, 1.1, 2.0.0 etc) and both collection and sub-collection are optional groups which follow <domain> restraints.

Current regex is: r'^(?P<domain_slug>[a-zA-Z0-9\-\_]*)\/(?P<version_slug>[a-zA-Z0-9\-\_\.]*)\/(?P<slug>[a-zA-Z0-9\-\_]+)\/$.

How can I capture optional positions, ensuring the last segment is always the page?

Additionally, is this even a good idea? Would it be better to just pass this through the Django URL conf and let a view function handle all the work?

Example URLs could include:
administration/5.0.3/reset-user-password
user/1.0/getting-started/setting-up-an-account
development/3.2/authentication/acl/creating-aco

R Down · Accepted Answer · 2017-08-31 07:34:10Z

1

(.*\/)([^\/]*)$ will put the page in $2 and something you'll have to parse in $1.

OP added:

The above did the trick. For reference, the full regex became (multi-lined for readability):

^(?P<domain>[a-zA-Z0-9\_\-]*)/ (?P<version>[a-zA-Z0-9\-\_\.]*)/ (?P<collections>.*)/ (?P<page>[^\/]*)$

edited Aug 31, 2017 at 7:34

R Down

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answered Aug 30, 2017 at 22:46

jesdynf

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1 Comment

R Down Over a year ago

This breaks things out the best for me - I just have to handle the collection group in-code, which is reasonable

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