Adding a day in time.struct_time object

Question

I am using a time.struct_time to set up the date and time and I want to add to the next day using a python script.

I am using following code:

date_1 = "31/08/2017 10:30PM"
time_1 = time.strptime(date_1, '%d/%m/%Y %I:%M%p')

Output:

time.struct_time(tm_year=2017, tm_mon=8, tm_mday=31, tm_hour=22, tm_min=30, tm_sec=0, tm_wday=3, tm_yday=243, tm_isdst=-1)

Now I want to add 1 day to this date. I used the following code:

time.struct_time(tm_year=2017, tm_mon=9, tm_mday=1, tm_hour=22, tm_min=30, tm_sec=0, tm_wday=3, tm_yday=243, tm_isdst=-1)

I am new on this, so can you please show me an example how I could add to the next day date using with my code?

TerryA · Accepted Answer · 2017-09-01 00:32:03Z

2

Honestly, I'm not sure if there even is a (clean) way. The data of a struct_time object are stored as tuples, so they are immutable. This means they can't really be modified in place.

I think you should be using the datetime module instead, like so:

>>> from datetime import datetime
>>> date_1 = "31/08/2017 10:30PM"
>>> time_1 = datetime.strptime(date_1, "%d/%m/%Y %I:%M%p")
>>> time_1
datetime.datetime(2017, 8, 31, 22, 30)

You can then add a month like so:

>>> from dateutil.relativedelta import relativedelta
>>> time_1 + relativedelta(months=1)
datetime.datetime(2017, 9, 30, 22, 30)

If you want to add a single day, then use datetime.timedelta(), which deals with the month's number of days:

from datetime import timedelta
time_1 + timedelta(days=1)

The reason I didn't use this above is because timedelta() doesn't take months as an argument

If you wish to convert it back to a string, then you use the strftime() function like so:

>>> new_time_1 = time_1 + relativedelta(months=1)
>>> print(datetime.strftime(new_time_1, '%d/%m/%Y'))
30/09/2017
>>> print(datetime.strftime(time_1, '%d/%m/%Y'))
31/08/2017

If for some reason you need to use the time module (say for one part of your code) but you want to convert it to the datetime object (for reasons like this), then I refer you to this question.

edited Sep 1, 2017 at 0:32

answered Aug 31, 2017 at 21:43

TerryA

60.2k11 gold badges122 silver badges148 bronze badges

Sign up to request clarification or add additional context in comments.

8 Comments

Daniel Ezekiel Over a year ago

thank you very much for this, I'm stored the date_1 string in the list so I could output them when I use date_1 = ''.join(str(x) for x in self.date_1). How I can get the date 31/08/2017 from the string and how I add it to the next day to make it show 1/09/2017 if there is possible to do in a different way?

TerryA Over a year ago

@DanielEzekiel Check my edit... does that answer your question?

Daniel Ezekiel Over a year ago

No not really, when you add the day it should add to the next month if my day is 29, 30, 31 or whatever its. Are there a way to do that without add the month, just the day?

TerryA Over a year ago

@DanielEzekiel Ah, that's where you'd do from datetime import timedelta; time_1 + timedelta(days=1). I didn't use this in my original answer since timedelta doesn't take a months argument

Daniel Ezekiel Over a year ago

Oh I see, so how would I know I need to add to the next month as some months has 30 and some months has 31?

|

jq170727 · Accepted Answer · 2017-09-01 00:02:46Z

1

Consider datetime.timedelta as explained in this question: Adding 5 days to a date in Python

answered Sep 1, 2017 at 0:02

jq170727

15k6 gold badges52 silver badges61 bronze badges

Collectives™ on Stack Overflow

Adding a day in time.struct_time object

2 Answers 2

8 Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

8 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related