Numpy: create random strings and make uniform

Question

I have tried the following code:

import numpy as np
let = ['A', 'B', 'C', 'D']
print(np.random.choice(let, 8, p=[0.25, 0.25, 0.25, 0.25]))

output:

['A' 'B' 'C' 'A' 'A' 'C' 'A' 'A']

It should be random but I want the following output: 25% A, 25%, B, 25% C, 25% D. Something like the following:

['A' 'B' 'C' 'A' 'C' 'D' 'D' 'B']

What am I missing?

So, the number of elements in output would be double of input? — Divakar
– Divakar, Commented Sep 16, 2017 at 20:38
The number of elements of output could by any length. I just choose 8 as an example. But the actually number could be any. For instance, 100 A's, 100 B's, 100 C's, 100 D's would also work. I just want each element to be 25% of total — SFC
– SFC, Commented Sep 16, 2017 at 20:43
You want random permutations of eight A's, eight B's, eight C's and eight D's. Correct? — Bill Bell
– Bill Bell, Commented Sep 16, 2017 at 20:48

SFC · Accepted Answer · 2017-09-16 21:17:25Z

1

Per RedEyed comment:

import numpy as np
let = ['A', 'B', 'C', 'D']
print(np.random.permutation(let*4))

answered Sep 16, 2017 at 21:10

SFC

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