Catch parameter from URL, pass parameter to a function, execute that function

Question

I have seen a case where for example a URL like this http://example.com/?edit=39 straight away opens a page where you can edit only the article/post which has ID = 39. I have read a lot about calling a function via URL but I have never met the case where you can catch parameter from the URL, pass the parameter into the function and then execute the function.

Using URL http://example.com/?edit=39 as example, how do I use a function to identify 39 as the ID and retrieve a post from the database which has ID = 39.

$id=$_REQUEST['edit'];

niteshd22
– niteshd22

2017-11-27 06:22:34 +00:00
Commented Nov 27, 2017 at 6:22 — niteshd22
– niteshd22, Commented Nov 27, 2017 at 6:22

Naren Verma · Accepted Answer · 2017-11-27 09:09:21Z

1

For example your URL is test.php?edit=39

if (isset($_GET['edit'])) {// it will catch the 39
    $id= $_GET['edit'];
     $return_value=funciton_name($id);// passing parameter to the function
     echo $return_value;// it will display the return vlaue.
}

//execute that function and return the value

function funciton_name($id){
    $result1 = "SELECT * FROM tablename WHERE id=".$id;
    return $result1;
}

answered Nov 27, 2017 at 9:09

Naren Verma

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1 Comment

Elizabeth Kof Over a year ago

@Narenda, thank you for this. You got me on the right path

seravee · Accepted Answer · 2017-11-27 06:44:12Z

1

Use parse_url() and parse_str() functions.

For example

$parts = parse_url($url); parse_str($parts['query'], $query); echo $query['email'];

If you want to get the $url dynamically have a look at this below question: Get the full URL in PHP

answered Nov 27, 2017 at 6:44

seravee

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2 Comments

Elizabeth Kof Over a year ago

Thank @seravee, however I did not understand $query['email']. where from the ['email']?

seravee Over a year ago

@Elizabeth Kof email is an argument if suppose it contains in the arguments i given as a sample format. for your URL it should be edit.

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