how to find bash script, then execute it and pass some arguments

Question

how to write the command??

I tried find . -name test.bash | xargs bash dd, this threw an error bash: xx: No such file or directory

I also tried find . -name test.bash | xargs bash -c, can't work too.

If the script is in the current directorybash script-name arg1 arg2 ...... argn. If it is in another directory then that directory should be in $PATH, it should be executable, and it should have a #! line. — cdarke
– cdarke, Commented Nov 27, 2017 at 15:12
Voting to close : "Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a *clear problem statement are not useful to other readers. See: [How to create a Minimal, Complete, and Verifiable example]stackoverflow.com/help/mcve)" . Good luck. — shellter
– shellter, Commented Nov 27, 2017 at 15:12
What happens when you run find . -name test.bash does it find anything? — Freiheit
– Freiheit, Commented Nov 27, 2017 at 15:13
Please also review the output from xargs with the -t (AKA --verbose) option. This will make xargs print out the command and argument it runs. man7.org/linux/man-pages/man1/xargs.1.html — Freiheit
– Freiheit, Commented Nov 27, 2017 at 18:41

Nic3500 · Accepted Answer · 2017-11-27 15:58:33Z

4

I created a test script, super simple, it just prints the arguments.

#!/bin/bash
echo "$@"

Then I find it in it's directory and call it with arguments:

find . -name test.bash -exec {} arg1 arg2 \;

It runs and outputs "arg1 arg2".

answered Nov 27, 2017 at 15:52

Nic3500

8,68410 gold badges33 silver badges45 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

@fujian26: good morning, please accept the answer (check mark on the left of the question).