How can I have multiple random outputs from a single line of code (python)

Question

How would I have a single line of code generate more than one random choice from a chosen list?

btw I do have import random at the top of the code

here is my code:

(R[0] = "RED", O[0] = "ORANGE", etc.)

ColourList = [R[0],O[0],Y[0],G[0],B[0],I[0],V[0]]
ColourSeq = random.choice(ColourList)
print(ColourSeq)

I know at the moment I have only asked it to give me one output, but I would like it to be able to give me four of the items from ColourList in just one line of code. There can be duplicate outputs.

nokta · Accepted Answer · 2017-11-28 16:11:03Z

2

You can use random.choices instead of random.choice. It is new in version 3.6.

ColourList = [R[0],O[0],Y[0],G[0],B[0],I[0],V[0]]
ColourSeq = random.choices(ColourList, k=6)
print(ColourSeq)

answered Nov 28, 2017 at 16:11

nokta

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1 Comment

Abhijith Asokan Over a year ago

nice.. i didn't knew about random.choices.. i guess i should delete my answer now :p

Rory Daulton · Accepted Answer · 2017-11-28 16:03:45Z

2

If you want to allow duplicate values, you can't use random.sample(). You can use a list comprehension:

ColourList = [R[0],O[0],Y[0],G[0],B[0],I[0],V[0]]
ColourSeq = [random.choice(ColourList) for x in range(4)]
print(ColourSeq)

If you want to print those values on separate lines, without the various additions of the list, replace the print statement with

print(*ColourSeq, sep='\n')

or with the longer but clearer

for v in ColourSeq:
    print(v)

If you want them printed on the same line but with the list stuff removed, just use the simple

print(*ColourSeq)

edited Nov 28, 2017 at 16:03

answered Nov 28, 2017 at 15:52

Rory Daulton

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2 Comments

matt6297 Over a year ago

Is there a way to remove the quotation marks, commas and square brackets from the answer? @RoryDaulton

Rory Daulton Over a year ago

@matt6297: Do my additions answer the question in your comment?

Ajax1234 · Accepted Answer · 2017-11-28 15:51:49Z

1

You can use list comprehension:

import random
ColourList = [R[0],O[0],Y[0],G[0],B[0],I[0],V[0]]
new_colors = [random.choice(ColourList) for i in range(4)]

answered Nov 28, 2017 at 15:51

Ajax1234

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Comments

ayoub aboussaad · Accepted Answer · 2017-11-28 15:55:47Z

0

you can use this

size = 2  
colors = random.sample(ColourList, size)

answered Nov 28, 2017 at 15:55

ayoub aboussaad

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1 Comment

colopop Over a year ago

random.sample samples without replacement. OP needs sampling with replacement.

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