I have an array
a=[0, 10, 20, 30, 40, 50, 60]
I selected the 2nd and 3rd element with
a[[1,2]]
obtaining
array([10, 20])
How do I select the other elements of a except the elements I've already selected?
That is, I want to obtain:
array([0, 30, 40, 50, 60])
Logically, should be something like
a[![1,2]]
Like this:
a=[0, 10, 20, 30, 40, 50, 60]
b = a[1:3]
c =[x for x in a if x not in b]
print(a)
print(b)
print(c)
Output:
[0, 10, 20, 30, 40, 50, 60]
[10, 20]
[0, 30, 40, 50, 60]
If order does not matter, you can stuff the list in a set and use these set operations:
yourSet.union(otherSet) , yourSet.intersect(otherSet) , yourSet.difference(otherSet) , etc
In case on python 2.7, the easiest solution is that:
a=[0, 10, 20, 30, 40, 50, 60]
c=[1,2]
values = [a[i] for i, x in enumerate(a) if i not in c]
print values
[0, 30, 40, 50, 60]
numpyif that is what you're asking about.aas shown (but not named) is a list.a[[1,2]]gives an error. Ifareally is a numpy array, you should show that in your code.