Kotlin lambdas without using objects

Question

I am trying to convert from java to kotlin. The current java interface is something like this:

interface MyInterface {
    void foo(int x, int y);
}

MyInterface testing = (int a, int b) -> System.out.print("TESTING");

My current kotlin conversion is:

interface MyInterface {
    fun foo(x:Int, y:Int)
}

val kotlinConversion = object: MyInterface {
    override fun foo(x: Int, y: Int) {
        println("TESTING")
    }
}

Is there a way to write the variable kotlinConversion such that it is similar to the one in java without having to override the function?

Do you need it to be an interface? A function type could potentially work just as well. — Qaz
– Qaz, Commented Dec 5, 2017 at 3:25
I think in order for any of us to answer, we need a better idea of your use case. What you have in Kotlin is not how one would do it in Kotlin. On the other hand, if you have a functional interface in Java, you can use a Lambda, and it will get cast/processed correctly. If it's all Kotlin code, then as chris said, you'll likely want a function type. Something like val kotlinConversion: (Int, Int) -> Unit = {x,y -> println("TESTING") } — Mikezx6r
– Mikezx6r, Commented Dec 5, 2017 at 3:28
This has been discussed here in kotlin forum. discuss.kotlinlang.org/t/kotlin-sam-traits-as-lambda-functions/… @Mikezx6r answer is the suggested solution. — jitinsharma
– jitinsharma, Commented Dec 5, 2017 at 4:10

Sasi Kumar · Accepted Answer · 2017-12-05 05:22:09Z

3

Without override the function you can directly use like this way

var kotlinConversion = { a: Int, b: Int -> print("TESTING") }

answered Dec 5, 2017 at 5:22

Sasi Kumar

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