Executing C program in BASH with 2 arguments

Question

I have a C program executable which required two arguments. The first argument is a abc.dat file and the second argument is abc.csv file. The program inputs the .dat file and converts it to a .csv file. The .dat exists when running the program and it creates the .csv which was the second argument.

I am trying to convert all the files in a folder using a bash script.

Here is my bash script:

#!/bin/sh

for file in /home/labadmin/Desktop/6122017/1252017
do
    ./my_read_bfee *.dat *.csv
done

When I execute the bash script I get:

usage: read_bfee in.dat out.csv

Please help. Thanks in advance.

Nahuel Fouilleul · Accepted Answer · 2017-12-06 15:21:35Z

2

maybe you wanted

#!/bin/sh

for file in /home/labadmin/Desktop/6122017/1252017/*.dat
do
    ./my_read_bfee "$file" "${file%.dat}.csv"
done

otherwise the *.dat inside the for loop is expanded to all files matching in current directory for each iteration

answered Dec 6, 2017 at 15:21

Nahuel Fouilleul

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