Assign different struct to variable in If-else block in golang

Question

I want to do something like this

type Struct1 {
    str1 string
}
type Struct2{
    int1 int
}

if something {
    someVar := Struct1{str1:''}
} else {
    someVar := Struct2{int1:1}
}

somefunc(someVar)

I know I can't declare c inside of one block and then access it outside.

I tried something like this

type Struct1 {
    str1 string
}
type Struct2{
    int1 int
}

someVar := Struct2{b:1}
if something {
    someVar := Struct1{a:''}
}

somefunc(c)

It gives an error- Cannot assign Struct1 to c(type Struct2)

How can I achieve something like this?

Possible duplicate of Why does golang compiler think the variable is declared but not used? — Jonathan Hall
– Jonathan Hall, Commented Dec 21, 2017 at 9:26

Roman Kiselenko · Accepted Answer · 2017-12-21 08:56:29Z

3

You can, use an interface{}

package main

import (
    "fmt"
)

type Struct1 struct {
    a string
}

type Struct2 struct {
    b int
}

func main() {
    var c interface{}
    if true {
        c = Struct1{a: ""}
    } else {
        c = Struct2{b: 1}
    }
    fmt.Printf("type %T", c)
}
// Print:
// type main.Struct1

https://play.golang.org/p/Z1cT9qjFmfU

answered Dec 21, 2017 at 8:56

Roman Kiselenko

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2 Comments

Bohdan Kostko Over a year ago

Still, I would recommend to use custom interface (type CustomStructInterface{}) instead of an empty one

Roman Kiselenko Over a year ago

@BohdanKostko indeed. In sake of simplicity I use an empty interface.

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