apply filter on a function in python

Question

I am getting an unexpected output when I execute the following python code. Iam new at python.

def foo(n):
    return n+2;
print (filter(foo,[1,2]))

i was expecting output as :-

[3,4]

but Iam getting output as:-

[1,2]

please help me solve this.

Miket25 · Accepted Answer · 2018-01-10 05:17:02Z

2

What you described is map and not filter.

def foo(n):
    return n+2;
print (map(foo,[1,2]))

Prints out

[3,4]

answered Jan 10, 2018 at 5:17

Miket25

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3 Comments

so you mean to say filter returns the original values after checking if it is true or not??

filter retains the values in the list that pass foo. e.g. def foo(n): return n>=2 print(filter(foo,[1,2])) will give [2].

...i got it. Thank you so much.