list = ['the dog ran', 'tomorrow is Wednesday', 'hello sir']
I want to search for the element containing the word Wednesday and replace that element with a line break at the beginning. So:
new_list = ['the dog ran', '/ntomorrow is Wednesday', 'hello sir']
Any help would be great. Everything I've tried has not worked. Thanks.
Processing the items in a list to make a new list calls for a list comprehension. Combine it with the x if y else z conditional expression to modify the items as you want.
old_list = ['the dog ran', 'tomorrow is Wednesday', 'hello sir']
new_list = [('\n' + item) if "Wednesday" in item else item for item in old_list]
You can use endswith in a list comprehension:
l = ['the dog ran', 'tomorrow is Wednesday', 'hello sir']
new_l = ['/n'+i if i.endswith('Wednesday') else i for i in l]
Output:
['the dog ran', '/ntomorrow is Wednesday', 'hello sir']
in is better than endswithList comprehension, and conditional expressions:
new_list = ['\n{}'.format(i) if 'Wednesday' in i else i for i in list_]
Example:
In [92]: l = ['the dog ran', 'tomorrow is Wednesday', 'hello sir']
In [93]: ['\n{}'.format(i) if 'Wednesday' in i else i for i in l]
Out[93]: ['the dog ran', '\ntomorrow is Wednesday', 'hello sir']
As a side note, setting your variable as list is a bad idea, as it shadows the builtin list type.
