Firebase Query an Array index value in Android

Question

How to list all recent where members 0th index equal to "5"?

@NileshRathod which didn't work for my scenario. The below answer is the correct one. Thanks. — Chathura Wijesinghe
– Chathura Wijesinghe, Commented Mar 19, 2018 at 3:57

Frank van Puffelen · Accepted Answer · 2018-03-19 03:53:18Z

1

Something like this should work:

DatabaseReference ref = FirebaseDatabase.getInstance().getReference("recent");
Query query = ref.orderByChild("members/0").equalTo("5");
query.addValueListener(new ValueEventListener() {
    @Override
    public void onDataChange(DataSnapshot dataSnapshot) {
        for (DataSnapshot childSnapshot: dataSnapshot.getChildren()) {
            System.out.println(childSnapshot.getKey());
        }
    }

    @Override
    public void onCancelled(DatabaseError databaseError) {            
        throw databaseError.toException());
    }
});

The trick here is that you specify the relative path to the property that you want to order/filter on in orderByChild().

answered Mar 19, 2018 at 3:53

Frank van Puffelen

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