PHP program to accept user input and terminate when entered zero

Question

I came across this program on http://www.programmr.com . And the question is Complete the program to print the sum of negative numbers, positive even numbers, positive odd numbers from a list of numbers entered by the user. The list terminates when the number entered is zero . And my code is,

$nums = array();

while(trim(fgets(STDIN)) != 0){
    array_push($nums,trim(fgets(STDIN)));
}

I know the code is incomplete but what im trying to do is to push the inputs to the array and then calculate the sum. When I print_r($nums) the array it gives me this,

Array
(
    [0] => 34
    [1] => 32
    [2] => 45
    [3] => 0
)

And my input is,

It pushes the alternative elements i dont know whats happening with this. Please help me , thanks in advance.

sietse85 · Accepted Answer · 2018-04-14 12:31:19Z

1

You are calling fgets(STDIN) twice in your code, i have adjusted it a bit so the array part is working. The rest of the assignment i let you figure that part out ;) Hint: Use modulus operator.

$nums = array();

do {
    $number = (int) trim(fgets(STDIN));
    array_push($nums,$number);
} while ($number !== 0);

print_r($nums);

Also if you are using PHP5.6 or higher you can use short array syntax like so:

$nums = [];

And

$nums[] = $number;

edited Apr 14, 2018 at 12:31

answered Apr 14, 2018 at 12:25

sietse85

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