Issue with ls -l and grep command in bash script

Question

I have piece of code and want it to search for a string in a particular path. The script will take input strings from an input file using a while loop. Basically, I want to read that file line by line and try to find out whether the content of that line exists in the particular path or not.

#!/bin/bash

filename='/input.txt'
path=/

while read -r line
do
    res=`ls -l $path | grep $line`
    echo "$res"
done < "$filename"

idownvotedbecau.se/imageofcode Please paste in your code using the appropriate code markdown. You should also go to the Help Center to see how to create a Minimal, Complete and Verifiable Example. — Mihai Chelaru
– Mihai Chelaru, Commented May 9, 2018 at 18:05
As the question stands, it is unclear exactly what problems you are facing. I suggest following chepner's advice and changing your file access strategy, if you are still facing issues, then edit your question with the relevant errors/code and a more specific explanation of what is blocking you — Will Barnwell
– Will Barnwell, Commented May 9, 2018 at 19:00
@WillBarnwell Hi, actually I have tried all the ways like using if command and after that I actually want to know what is the actual output so I have commwnted for some. — chandu
– chandu, Commented May 10, 2018 at 2:27

Acorn · Accepted Answer · 2018-05-10 03:10:15Z

1

Instead of ls, use find:

find $file -maxdepth 1

If you need to grep for the full paths, ensure that you are passing the absolute/canonical path to find:

find `readlink -f $file` -maxdepth 1

edited May 10, 2018 at 3:10

answered May 10, 2018 at 3:05

Acorn

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