JSON encoder returns Optional()

Question

I am trying to encode my jsonData. All works fine with one exception - I am receiving as output Optional(my_json_string). But I want to receive only my_json_string

When I change req.httpBody = jsonData to req.httpBody! = jsonData, I am getting an error.

do {
    let jsonData = try encoder.encode(self)
    let jsonString = String(data: jsonData, encoding: .utf8)
    req.httpBody = jsonData
    print ("httpBody is: ", jsonString)
} catch {
    //TODO:error handling
}

How to do it correctly and unwrap my JSON string from optional?

David Pasztor · Accepted Answer · 2018-05-15 18:21:16Z

6

There's no issue with your code, your encoded JSON isn't Optional. The issue you see is that you are printing the return value of the String(data:, encoding: ) initializer, which is a failable initializer (it returns nil if the encoding you supplied to it is wrong), hence the Optional in the print statement.

JSONEncoder always produces a valid UTF-8 encoded String, so you can safely force unwrap the return value of the initializer by doing

let jsonString = String(data: jsonData, encoding: .utf8)!

answered May 15, 2018 at 18:21

David Pasztor

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