python split string and list full path name

Question

I am using glob to get a list of all PDF files in a folder (I need full path names to upload file to cloud)

also, during the upload I need to assign a "title" to the file which we be the items name in the cloud.

I need to split the last "\" and the "." and get the values in between. for example:

pdf_list = glob.glob(r'C:\User\username\Desktop\pdf\*.pdf')

a item in the list will be: "c:\User\username\Desktop\pdf\4434343434331.pdf"

I need another pythonic way to grab the pdfs file name in a separate variable while still in the for loop.

for file in pdf_list:
    upload.file
    file.title(file.split(".")[0]

however the above split will not return my desired results but something along those lines

I am using a for loop to upload each pdf (using file path)

Matias Cicero · Accepted Answer · 2018-05-16 22:45:03Z

4

Actually, there is a function for this already:

for file in pdf_list:
   file_name = os.path.basename(file)
   upload.file(file_name)

answered May 16, 2018 at 22:24

Matias Cicero

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1 Comment

this worked but left the ".pdf" suffix. I was able to use file_name.split(".")[0] to get the desired results. thanks!

A K · Accepted Answer · 2018-05-16 22:36:19Z

1

You can use pathlib, for example:

from pathlib import Path
p = list(Path('C:/User/username/Desktop/pdf').glob('*.pdf'))
first_filename = p[0].name

answered May 16, 2018 at 22:36

A K

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