How do I use the sorted key function call in Python?

Question

I have a list of strings that represents playing cards. Ranks can be

A23456789TJQK

Here is my list

# L2
['5', '6', '7', 'A', 'K']

And I'm trying to make a function to call with the key in the sorted function to return the card rank numerical values in order. So here is my function:

def sortYo():
   myDict = {'A': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9, 'T': 10, 'J': 10, 'Q': 10, 'K': 10}

And here is my call:

L4 = sorted(L2, key = sortYo())

But my L4 ends up the same:

# L4
['5', '6', '7', 'A', 'K']

Why isn't my sortYo() function changing the values? Thank you in advance.

EDIT:

from collections import Counter
from itertools import combinations
import sys


myList = sys.argv
myList.pop(0)
Suits = ['H', 'S', 'D', 'C']
Nums = ['A', '2', '3', '4', '5', '6', '7', '8', '9', 'T', 'J', 'Q', 'K']
SuitsTwo = {'♥': 'H', '♦': 'D', '♣': 'C', '♠': 'S'}
print(myList)
L1 = [] # Suits
L2 = [] # Ranks
L3 = [i for i in myList[0]] # Cut
for i in myList:
   for x in i:
      if x in SuitsTwo:
         L1.append(SuitsTwo[x])
      elif x in Suits:
         L1.append(x)
      else:
         L2.append(x)

print('L1:'
print(L1)
print('L2:')
print(L2)
print('L3:')
print(L3)
score = 0
# straight
sC = 0
myDict = {'A': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9\
': 9, 'T': 10, 'J': 10, 'Q': 10, 'K': 10}

L4 = sorted(L2, key = lambda x: myDict.get(x,11))
print('L4')
print(L4)

#RUN
python3 as13.py AS 5H 6C 7S KH
['AS', '5H', '6C', '7S', 'KH']
L1:
['S', 'H', 'C', 'S', 'H']
L2:
['A', '5', '6', '7', 'K']
L3:
['A', 'S']
L4
['A', '5', '6', '7', 'K']
0

... Because you don't return anything.

Ignacio Vazquez-Abrams
– Ignacio Vazquez-Abrams

2018-05-24 01:27:52 +00:00
Commented May 24, 2018 at 1:27 — Ignacio Vazquez-Abrams
– Ignacio Vazquez-Abrams, Commented May 24, 2018 at 1:27

Olivier Melançon · Accepted Answer · 2018-05-24 02:20:21Z

3

Try using a lambda function for the sorting key:

myDict = {'A': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, 
          '9': 9, 'T': 10, 'J': 10, 'Q': 10, 'K': 10}

L4 = sorted(L2, key=lambda x: myDict.get(x, 11))

This will sort by the values associated to each key in myDict. It will also place any value in L2 that is not in the keys of myDict at the end of the sorted list by assigning a default value of 11 to unknown keys.

If you don't have to worry about items in L2 that are not in the keys of myDict, you can also use:

L4 = sorted(L2, key=myDict.get)

edited May 24, 2018 at 2:20

Olivier Melançon

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answered May 24, 2018 at 1:34

James

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7 Comments

Olivier Melançon Over a year ago

Remove the lambda, just let key=myDict.get

James Over a year ago

Good point, but you can't include the default value. I will add it.

Olivier Melançon Over a year ago

I dont think you should expect a missing value, we are talking about cards, we know all the possible values

Coder117 Over a year ago

I tried this method and the other one but I'm still not getting anything happening. Should I edit the question to show what's happening?

Olivier Melançon Over a year ago

@Coder117 well it worked, the list was already sorted, remember your ace is worth 1

|

Ignacio Vazquez-Abrams · Accepted Answer · 2018-05-24 01:28:43Z

3

sorted(..., key='A23...JQK'.index)

answered May 24, 2018 at 1:28

Ignacio Vazquez-Abrams

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4 Comments

Ignacio Vazquez-Abrams Over a year ago

Fortunately there aren't any (10 uses "T" instead).

Coder117 Over a year ago

@IgnacioVazquez-Abrams Thanks. I'm still not getting anything happening though. You mentioned in another comment that I'm not returning anything. What am I supposed to return in the sortYo() function? Am I supposed to return myDict?

Ignacio Vazquez-Abrams Over a year ago

You're supposed to return the desired key for the value that gets passed to it.

Coder117 Over a year ago

I tried returning myDict[i] but I'm still not getting anything. Any ideas?

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