How to create a new oracle database with hibernate

I am new to hibernate and I am following a tutorial of hibernate within Java EE application, here is my persistence.xml file:

<persistence xmlns="http://xmlns.jcp.org/xml/ns/persistence"
             xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
             xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence
             http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd"
             version="2.1">

    <persistence-unit name="punit">

    </persistence-unit>
</persistence>

And here my hibernate configuration it is in file called jpaContext.xml.

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:tx="http://www.springframework.org/schema/tx"
    xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.2.xsd
        http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.2.xsd">

    <bean id="entityManagerFactory"
        class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="persistenceUnitName" value="punit" />
        <property name="dataSource" ref="dataSource" />
        <property name="jpaVendorAdapter">
            <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
                <property name="showSql" value="true" />
            </bean>
        </property>

        <property name="jpaPropertyMap">
            <map>
                <entry key="hibernate.dialect" value="org.hibernate.dialect.Oracle10gDialect" />
                <entry key="hibernate.hbm2ddl.auto" value="create" />
                <entry key="hibernate.format_sql" value="true" />
            </map>
        </property>
    </bean>

    <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
        <property name="entityManagerFactory" ref="entityManagerFactory" />
    </bean>
    <tx:annotation-driven transaction-manager="transactionManager" />
    <bean id="dataSource"
        class="org.springframework.jdbc.datasource.DriverManagerDataSource">
        <property name="driverClassName" value="oracle.jdbc.driver.OracleDriver" />
        <property name="url" value="jdbc:oracle:thin:@localhost:1521:orcl" />
        <property name="username" value="SYS AS SYSDBA" />
        <property name="password" value="password" />
    </bean>

The problem I have is when I start the server (for first time) no new database is created but only a table for an entity I have in my application, within the SYS schema as you can see in the image below:

Here is the entity which table is created:

package com.pluralsight.model;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Table;
import javax.persistence.Id;

import org.hibernate.validator.constraints.Range;

@Entity
@Table(name="goals")
public class Goal {

    @Id 
    @GeneratedValue
    private Long Id;

    @Range(min = 1, max = 120)
    @Column(name="MINUTES")
    private int minutes;

    public int getMinutes() {
        return minutes;
    }

    public void setMinutes(int minutes) {
        this.minutes = minutes;
    }

    public Long getId() {
        return Id;
    }

    public void setId(Long id) {
        Id = id;
    }

}

While what I am looking for is to create the new database instance (if it does not exist) for the application I am developing and to give it (the same that the application for example )

Does anyone know how can I achieve this with hibernate ?