Assign two lines of output to two different variables in bash

Question

I am writing a Bash script where I have to list the AWS access keys for a user, and then assign them to variables.

A user may have two access keys. So the user will need two variables to store those keys.

This is the line I have so far:

aws iam list-access-keys --user-name "$user_name" --profile="$aws_key"  | grep -i accesskeyid | awk '{print $2}' | sed 's/"//g'

The output would be something like this:

 AKIAJS7KDACQRQ5FJWA
 AKIAICDDTVTMEAB6RM5Q

How can I assign each of those to its own variable in Bash?

tripleee · Accepted Answer · 2018-06-04 18:18:12Z

1

You can use a parameter substitution to split the string on a newline. ${variable%$'\n'*} obtains the portion of the value of $variable before the last newline, and ${variable#*$'\n'} gets the portion after the first newline.

As an aside, Awk generally can do anything grep and sed can do.

variable=$(aws iam list-access-keys --user-name "$user_name" --profile="$aws_key"  |
awk 'tolower($0) ~ /accesskeyid/{gsub(/\"/,""); print $2}')

edited Jun 4, 2018 at 18:18

answered Jun 4, 2018 at 18:12

tripleee

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1 Comment

chepner Over a year ago

{ read var1; read var2; } <<< "$variable" might be simpler (or even { read var1; read var2; } < <( aws ... | awk '...').

Benjamin W. · Accepted Answer · 2018-06-04 20:54:09Z

0

You can do the processing as part of the aws command already, using a --query:

aws iam list-access-keys --user-name "$user_name" --profile="$aws_key" \
    --query 'AccessKeyMetadata[*].AccessKeyId' --output text

returns the IDs in a tab separated line, so you could do something like

read -a vars <<< \
    $(aws iam list-access-keys --user-name "$user_name" --profile="$aws_key" \
    --query 'AccessKeyMetadata[*].AccessKeyId' --output text)

and you get an array vars containing your variables.

edited Jun 4, 2018 at 20:54

answered Jun 4, 2018 at 20:09

Benjamin W.

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