Python sorting numerically in text file

Question

Hi I'm working on a mini game that store user's time taken to complete the game as their score. I'm able to append the scores into my text file but I failed to sort them.

example: 17.25 jason 18.5 simon 20.12 ben

def scoring():
    #appending level 1 score
    L1=[]
    L1.append((Timetaken,myname))
    with open('L1.txt','a') as x:
        x.write('%f,%s'%(Timetaken,myname))
def arranging():
    #Sorting level 1
    column=[]
    with open('L1.txt') as file1:
        for line in file1:
            column.append(line.split('\n'))
    sorted(column,key=itemgetter(0),reverse=False)
    with open("L1.txt",'w+') as first:
        for x in column:
            if (len(column))<=10:
            first.write(str(x)+str(' , '))`

You will get more and better answers if you create a Minimal, Complete, and Verifiable example. Especially make sure that the input and expected test data are complete (not pseudo-data), and can be easily cut and and paste into an editor to allow testing proposed solutions. — Stephen Rauch
– Stephen Rauch ♦, Commented Jun 13, 2018 at 2:58
what is Timetaken? please show an stackoverflow.com/help/mcve — CIsForCookies
– CIsForCookies, Commented Jun 13, 2018 at 2:58

ZaxR · Accepted Answer · 2018-06-13 03:01:16Z

1

Your issue is that sorted() doesn't sort in place. You need to do:

column = sorted(column,key=itemgetter(0),reverse=False)

answered Jun 13, 2018 at 3:01

ZaxR

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