javascript variable doesn't show validation errors of codeigniter in the form

Question

i'm using ci built-in validation_errors() function in my login form. everything works fine and i can see true validation errors in my view. but when i echo validation errors into my js variable in the script to show it in the customized notifications, nothing shows. here is my code:

    <?php if (isset($validation_error)){
        echo $validation_error;} ?>
    <script>
        var text=  "<?php echo $validation_error;?>";
    </script>
    <script src="<?php echo base_url();?>resources/js/assets/errore-not.js" type="text/javascript">
    </script>

when i pass any php variables or strings in "text" variable of script, it shows the notification correctly. this is my notify code:

$(document).ready(function notification () {
    $.notify({
        icon: "notifications",
        message: text

    }, {
        type: 'danger',
        timer: 4000,
        placement: {
            from: 'top',
            align: 'center'
        }
    });
});

How can I do this?

<script> var text= $validation_error; </script> here you allocate php variable without php tag to javascript variable... — Ashu
– Ashu, Commented Jun 21, 2018 at 6:07
i've been used this mechanism to show upload errors of ci in exactly this way and it works fine.the return value of this function: $this->upload->display_errors() @Teemu — top.eng
– top.eng, Commented Jun 21, 2018 at 6:11
The original source code was var text= $validation_error; which certainly won't work. Later you've edited the code to a working version. — Teemu
– Teemu, Commented Jun 21, 2018 at 6:40
In Firebug or on chrome inspect, are you getting any errors or warnings? — Mangesh Sathe
– Mangesh Sathe, Commented Jun 21, 2018 at 6:48
To test your $.notify call just hard-code message: 'my temp text' and check if its working. If its not wroking then you have check notify call first — Mangesh Sathe
– Mangesh Sathe, Commented Jun 21, 2018 at 6:51

F5 Buddy · Accepted Answer · 2018-06-21 08:38:10Z

2

You can pass the php variable value inside javascript variable like this.

<?php if (isset($validation_error)){
    echo $validation_error; ?>
<script>
    var text= '<?php echo $validation_error;?>';
</script>
<?php } ?>

edited Jun 21, 2018 at 8:38

answered Jun 21, 2018 at 6:09

F5 Buddy

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1 Comment

top.eng Over a year ago

tnx but my code was like this before and it didn't work for me.

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