infinite Fibonacci generator in python with yield error?

Question

def fib_gen():
    a, b = 0, 1
    while True:
        yield a
        a, b = b, a + b

print(next(fib_gen())) 
print(next(fib_gen())) 
print(next(fib_gen())) 
print(next(fib_gen()))

Output: 0 
        0 
        0 
        0

I am trying to create an infinite Fibonacci generator in python. Please help ... Where am I doing wrong ?

Thanks but No @insaner.. In infinite series I get this code from web everywhere.. but it is resetting the value of a every-time it is called. — Sameer Pradhan
– Sameer Pradhan, Commented Jul 1, 2018 at 5:39

Tugrul Ates · Accepted Answer · 2018-07-01 05:39:59Z

6

Each call to fib_gen() creates a new generator that is in initial state. Try assigning the return value of fib_gen() to a variable and calling next() on that same variable.

answered Jul 1, 2018 at 5:39

Tugrul Ates

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Comments

user9145571 · Accepted Answer · 2018-07-01 05:43:08Z

5

You first need to create a generator object:

def fib_gen():
    a, b = 0, 1
    while True:
        yield a
        a, b = b, a + b


generator = fib_gen()

print(next(generator))
print(next(generator))
print(next(generator))
print(next(generator))

The output is:

answered Jul 1, 2018 at 5:43

user9145571

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