Update element in the list in Python

Question

I have a list of binary number, its about 100 elements in a list:

a='11010010'
n = 2
split=[a[i:i+n] for i in range(0, len(a), n)]

The result showing like this:

split =['11', '01', '00', '10', '01', '10', '11'.....]

My question is how to assign if else looping for my list? The problem is the list need to updated automatically based on the value of the elements.

For example, if '11'=3*2, '01'=7*4, '00'=5*6, '10'=4*8

And I want my result updated to this:

split =[6,28,30,32,28,32, 6 .....]

Thanks a lot! ;)

it is a, not encode. Sorry for the typo. split=[a[i:i+n] for i in range(0, len(a), n)] yes..it is a="11010010" — Zie
– Zie, Commented Jul 4, 2018 at 23:18

jpp · Accepted Answer · 2018-07-04 23:49:49Z

1

The problem is the list need to updated automatically based on the value of the elements.

Setting aside the rest of your question, which to me is unclear, you can achieve this goal via a dictionary. First define a dictionary mapping:

d = {'11': 6, '01': 28, '00': 30, '10': 32}

Then, using map or a list comprehension, apply the mapping to the elements of your list:

# map
res = list(map(d.get, split))

# list comprehension
res = [d[i] for i in split]

print(res)

[6, 28, 30, 32, 28, 32, 6]

answered Jul 4, 2018 at 23:49

jpp

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1 Comment

Zie Over a year ago

This is very helpful. Thank you so much. ;)

Rushabh Mehta · Accepted Answer · 2018-07-04 23:24:29Z

0

This is a pretty unclear question, given that encode isn't a standard python function, and saying that '11'=3*2 doesn't make much sense, but I'll try to point you in the right direction here.

A lot of the if-else looping in Python can be done with list comprehensions. These structures allow you to construct lists based on conditions and loops you specify. They tend to have the following structure

[value(i) for i in list if condition else value2(i)]

You can try to use this to solve your problem!

answered Jul 4, 2018 at 23:24

Rushabh Mehta

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4 Comments

Zie Over a year ago

Noted and thank you so much. I will try this code later.

Rushabh Mehta Over a year ago

No problem man! If you like my answer, make sure to vote and give best answer as appropriate! (green tick on the left)

jpp Over a year ago

In my opinion, this is not recommended if you have multiple if / else conditions. This works for a single replacement but becomes unreadable for multiple.

Rushabh Mehta Over a year ago

@jpp I agree. However, I just don't know what exact conditions he wants, so going down the list comprehension route at least gives him a starting point.

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