How to execute BASH source command from scala 2.11?

Question

How do I execute BASH 'source' command using scala 2.11?

import scala.sys.process.Process

object putFileToHDFS {
  def main(args: Array[String]): Unit = {
    println("""In class putFileToHDFS""");

    val tester = Process("source ./trial.sh").lineStream;
    tester.foreach(println)


  }
}

Possible duplicate of Execute shell script from scala aplication — Rene Knop
– Rene Knop, Commented Jul 13, 2018 at 6:23
What does it even mean to "source" a bash script from Scala? Since Scala is by definition not bash, it obviously cannot "source" files with bash definitions. Unclear what you expected to happen. — Andrey Tyukin
– Andrey Tyukin, Commented Jul 13, 2018 at 11:33

jwvh · Accepted Answer · 2018-07-13 06:48:07Z

1

I think this is the equivalent of what source does.

import scala.sys.process._

              //send file contents to sh for interpretation
val tester = "/bin/cat /path/trial.sh".#|("/bin/sh").lineStream

Of course, things are much easier if trial.sh is executable.

val tester = "/bin/sh -c /path/trial.sh".lineStream

edited Jul 13, 2018 at 6:48

answered Jul 13, 2018 at 6:43

jwvh

51.3k7 gold badges42 silver badges70 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

cbley · Accepted Answer · 2018-07-13 08:32:07Z

1

You do not need to source the script file, since you only need to do that when you want to include a script from another one. All you need to do is run it:

Process("bash trial.sh").lineStream

answered Jul 13, 2018 at 8:32

cbley

4,6181 gold badge20 silver badges33 bronze badges

Collectives™ on Stack Overflow

How to execute BASH source command from scala 2.11?

2 Answers 2

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related