How to dynamically set a control using variables C#

Question

How do you dynamically call a control and set it property at runtime?

// Declare and set queue servers
string[] queueservers = new string[] { "SERVER1", "SERVER2", "SERVER3", "SERVER4" };
int y;

for (y = 0; y <= queueservers.Length - 1; y++)
{
   string queueanswer = GetMailQueueSize(queueservers[y]);
   if (queueanswer == "alarm")
   {
      phxQueueImg + queueservers + .ImageUrl = "~/images/Small-Down.gif";
   }
   else
   {
      phxQueueImg + queueservers + .ImageUrl = "~/images/Small-Up.gif";
   }
   queueanswer = "";
}

I suspect you just want to get a control given then name of the control -- if this is the case, I would advise using a Dictionary<name,Control> or similar (although perhaps the general design is icky?) The Controls collection can be manually iterated -- but more ick. — user166390
– user166390, Commented Mar 2, 2011 at 5:41

Community · Accepted Answer · 2017-05-23 12:32:50Z

1

See here about asking good questions .

I'm going to assume you pasted the wrong code since it doesn't seem to have anything to do with the question afaik. Plus could edit your question and tag if this is winform, wpf or web?

Here I dynamically create the control at runtime:

Textbox c = new Textbox();

Set its text, eg

string s = "Please paste code that relates to your question";
c.Text = s;

Or here I dynamically set my textbox controls property using variables:

propertyInfo = c.GetType().GetProperty(property); 
if (propertyInfo != null)
{
    propertyInfo.SetValue(c, value, null);
}

edited May 23, 2017 at 12:32

CommunityBot

11 silver badge

answered Mar 2, 2011 at 5:38

Jeremy Thompson

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1 Comment

user674989 Over a year ago

I know I'm a little late to the party but that last block just helped me out.

Numan · Accepted Answer · 2011-03-02 05:44:27Z

0

try FindControl("controlID") and then cast the result of this call to the required control type and set the needed property.

(SomeParentControl.FindControl("IDOfControlToFind") AS LinkButton).PostBackUrl = "~/someresource.aspx";

answered Mar 2, 2011 at 5:44

Numan

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