Bash Script to execute linux file

Question

As shown in the image below, I have a Linux executable and it can be run using this command:

./bomb filename0.txt

I need a bash script to run this continuously as I have various files that I want to run the executables with as shown in the picture such as filename0, filename1, filename and so on.

How could I automate the execution of my script with all these files as argument?

aydow · Accepted Answer · 2018-08-06 10:53:39Z

1

Use bash. This script will execute bomb on every file in your directory

for file in /path/to/dir/*.txt
do
  path/to/bomb "$file" >> results.out
done

Example

[20:37:04] ado@crystal
± >  touch a b c

[16:47:26] ado@crystal
± >  ls
a b c

[16:47:27] ado@crystal
± >  for i in *; do echo "this is $i"; done
this is a
this is b
this is c

edited Aug 6, 2018 at 10:53

answered Aug 6, 2018 at 6:45

aydow

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1 Comment

vmonteco Over a year ago

Be careful, this will pass bomb as an argument to itself. If the argument files names are consistent, consider filtering with *.txt to avoid that.

codegrep_admin · Accepted Answer · 2018-08-06 06:46:45Z

0

for i in `seq 0 10`
do
 ./bomb filename$i.txt
done

The above code will run from filename0 to filename10

answered Aug 6, 2018 at 6:46

codegrep_admin

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2 Comments

JohnBash Over a year ago

Thanks !! I was mixed up the syntax with python as I put filename{1}!! No wonder

vmonteco Over a year ago

This works in this precise case, but you're limited to patterns where filenames contain a number you iterate on. I think aydow's answer is more generic.

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