Python object attributes as variables

Question

I am trying to assign a python object attribute a variable. Here is what I have been trying to do:

from read import *
import matplotlib.pyplot as plt
import numpy as np

data=table('data.txt')

semi=data['data']['a']
ecc = data['data']['e']
incl= data['data']['i']
bias = data['data']['bias']    

fig = plt.figure()
ax1 = fig.add_axes([0.06, 0.1, 0.4, 0.35])
ax2 = fig.add_axes([0.06, 0.6, 0.4, 0.35])
ax3 = fig.add_axes([0.55, 0.6, 0.4, 0.35])
ax4 = fig.add_axes([0.55, 0.1, 0.4, 0.35])

aaa = getattr(ax1,'xaxis')


nax={'ax1':ax1,'ax2':ax2,'ax3':ax3,'ax4':ax4}

for a in sorted(nax):

  aax = {'xaxis':nax[a].get_xaxis()}
  for axis in ['bottom','left']:
     nax[a].spines[axis].set_linewidth(0.5)
  for axis in ['right','top']:
     nax[a].spines[axis].set_visible(False)
  for b in sorted(aax):
     nax[a].b.set_tick_position('bottom')

When I run my code it says:

Traceback (most recent call last):
  File "./test1.py", line 35, in <module>
    ax1.b.set_ticks_position('bottom')
AttributeError: 'Axes' object has no attribute 'b'

Originally it works when:

ax1.xaxis.set_tick_position('bottom')

but I need to make the XAxis attribute a variable for the sake of creating plotting templates. Any idea how to make the above thing work?

getattr gets an attribute. If you want to set an attribute, you need setattr. But there’s rarely a need for either—you can just do ax1.x = ax1.axis instead of setatrr(ax1, 'x', getattr(ax1, 'axis')). — abarnert
– abarnert, Commented Sep 9, 2018 at 2:59
@abarnert Thank you so much! But ax1.x=ax1.xaxis will be in a for loop because I have many axes e.g., ax1, ax2, ax3, ax4,.... so I want to loop the xaxis attribute over all axes e.g., nax={'ax1':ax1,'ax2':ax2,'ax3':ax3,'ax4':ax4} for a in sorted(nax): nax[a].x.set_ticks_position('bottom') — user3578925
– user3578925, Commented Sep 9, 2018 at 3:17

Matt Messersmith · Accepted Answer · 2018-09-09 02:50:15Z

2

Try x.set_tick_position('bottom') instead of ax1.x.set_tick_position('bottom'). x is already an attribute off of the ax1 object, so you don't need to access ax1 again.

Furthermore, no need for getattr if you know the name of the attribute statically. You can just do x = ax1.xaxis.

answered Sep 9, 2018 at 2:50

Matt Messersmith

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2 Comments

user3578925 Over a year ago

Thank you so much! That works, but my axes are variables as well. Actually, here is a larger portion of what I've been trying to accomplish:

fig = plt.figure() ax1 = fig.add_axes([0.06, 0.1, 0.4, 0.35]) ax2 = fig.add_axes([0.06, 0.6, 0.4, 0.35]) ax3 = fig.add_axes([0.55, 0.6, 0.4, 0.35]) ax4 = fig.add_axes([0.55, 0.1, 0.4, 0.35])  x = getattr(ax1,'xaxis') nax={'ax1':ax1,'ax2':ax2,'ax3':ax3,'ax4':ax4}  for a in sorted(nax):   for axis in ['bottom','left']:      nax[a].x.set_ticks_position('bottom')

Matt Messersmith Over a year ago

Sweet. I see you've accepted the answer. Mind upvoting if you found this useful?

ImportanceOfBeingErnest · Accepted Answer · 2018-09-09 11:24:55Z

0

I would suggest to work on the objects directly.

nax=[ax1,ax2,ax3,ax4]

for ax in nax:

   for axis in ['bottom','left']:
       ax.spines[axis].set_linewidth(0.5)
   for axis in ['right','top']:
       ax.spines[axis].set_visible(False)

   ax.xaxis.set_tick_position('bottom')

answered Sep 9, 2018 at 11:24

ImportanceOfBeingErnest

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