bash script for create child process for ssh

Question

i want remote log for several hosts and check some configuration. for that i wrote a small script. it have two files. one for ip address list and other for script.

cat iplist
192.168.1.10
192.168.1.11
192.168.1.12

My script:

cat script.sh
#!/bin/bash
while read ip;
 do
    sshpass -p 'root' ssh  root@$ip "hostname"
    echo "$ip" 
done < iplist

above script only display one hostname and one IP only

P.P · Accepted Answer · 2018-10-24 09:30:02Z

1

ssh reads in from stdin and consumes all of your input file ip_list when its run the first time. You can use -n option to ssh command line to instruct it to not so.

Other ways are to use a different file descriptor for reading from ip_list or redirect input with ... </dev/null.

answered Oct 24, 2018 at 9:30

P.P

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2 Comments

Lahindu Mihirantha Over a year ago

i didn't get it. could you please explain

P.P Over a year ago

You pass -n option such as ssh -n root@$ip "hostname". Otherwise, ssh would read in standard input (in your case, you are passing input from a file, so it'd read in the whole file in one go). See the man page and read -n's description: man7.org/linux/man-pages/man1/ssh.1.html

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