I need to copy a file from one directory to another and do something with that file. I need to copy it with cmd, rather than File.Copy(), because I need the copy to be done as a part of ProcessStartInfo.
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3 Answers
You can use this code and change startInfo.Arguments, but /C should be!
System.Diagnostics.Process process = new System.Diagnostics.Process();
System.Diagnostics.ProcessStartInfo startInfo = new
System.Diagnostics.ProcessStartInfo();
startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
startInfo.FileName = "cmd.exe";
startInfo.Arguments = "/C copy example.txt backup.txt";
process.StartInfo = startInfo;
process.Start();
1 Comment
Petar
Thanks,
/C definitely helped!You can create a bat-file to copy one or multiple files (using *). Then execute the batch file.
string batFileName = @"C:\{filePath}\copy.bat";
System.IO.File.WriteAllText(batFileName, @"copy {fileName}.{extension} {destination-filePath}");
System.Diagnostics.Process.Start(batFileName);
Comments
I was able to formulate this answer using the DOS Copy syntax along with this Stack Overflow QA Start cmd window and run commands inside
var startInfo = new ProcessStartInfo {
FileName = "cmd.exe",
RedirectStandardInput = true,
RedirectStandardOutput = true,
UseShellExecute = false,
CreateNoWindow = true
};
var process = new Process {StartInfo = startInfo};
process.Start();
process.StandardInput.WriteLine(@"copy c:\Source\Original.ext D:\Dest\Copy.ext");
process.StandardInput.WriteLine("exit");
process.WaitForExit();
