Let's say I have this string:
"14 be h90 bfh4"
And I have this regex pattern:
"(\w+)\d"
In PowerShell, how do I get an array with the contents {"h", "bfh"}?
3 Answers
You want to capture one or more alphabets that are followed by a number, hence the regex for what you want to capture would be this,
[a-zA-Z]+(?=\d)
And the powershell code for same will be this,
$str = "14 be h90 bfh4"
$reg = "[a-zA-Z]+(?=\d)"
$spuntext = $str | Select-String $reg -AllMatches |
ForEach-Object { $_.Matches.Value }
echo $spuntext
Disclaimer: I barely know powershell scripting language so you may have to tweak some codes.
answered Nov 26, 2018 at 6:29
Pushpesh Kumar Rajwanshi
18.4k2 gold badges22 silver badges39 bronze badges
2 Comments
Lieven Keersmaekers
The powershell part does need rework but the gist of it looks good
Pushpesh Kumar Rajwanshi
Thanks @LievenKeersmaekers. I actually just googled about powershell and came up with this. I've never got a chance to use powershell before. But its good, everything has a first time :)
A bit shorten version:
@(Select-String "[a-zA-Z]+(?=\d)" -Input "14 be h90 bfh4" -AllMatches).Matches.Value
Comments
Multiple ways to skin a cat as demonstrated by the other answers. Yet another way would be by using the [regex] object provided by .Net
$regex = [regex] '([a-z]+)(?=\d+)'
$regex.Matches("14 be h90 bfh4") | Select Value
answered Nov 26, 2018 at 6:38
Lieven Keersmaekers
58.9k15 gold badges117 silver badges151 bronze badges
$array = ($string -split '(\s)') -replace '[^a-zA-Z-]','' | SELECT-STRING -Pattern '([A-Z])'$result = Select-String '\b(\p{L}+)\d+\b' -Input "14 be h90 bfh4" -AllMatches|%{$_.Matches.Groups[1].Value}