function Outer(){
var a=10;
function Inner(){
var a = 20;
console.log(a);
}
Inner();
}
Outer();
In this codek I want the inner function to print the value of outer function's a(i.e 10). How do I achieve this?
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1 Answer
When you delcare var a = 20; on the fourth line above, you're redeclaring a variable that is already in scope and assigning it a new value. So the new value is what you get. If you remove that declaration, the name a will refer to the variable declaration in the outer scope and you'll get 10.
2 Comments
Ananthula Snigdha
Hi Stephen, I've tried it but it's still printer the variable in the inner scope. I've found that bind() will helps to resolve this problem but i'm unable to figure it out.
Stephen Crosby
You must not have tried the same thing I'm trying. Take a look at this example on jsbin where I commented out the inner variable declaration: jsbin.com/taneyoviro/edit?html,output
