Can I find the index of the changed value by comparing two arrays?
For exaple;
array1 = [1, 2 ,3]
array2 = [1, 2, 4]
I want to find the index of the changing value by comparing these two arrays. For this example this should be 2.
I am using numpy to compare two arrays. But I can't find the index of changed value(s).
Since you are using NumPy, you can compare using the != operator and use np.flatnonzero:
array1 = np.array([1,2,3])
array2 = np.array([1,2,4])
res = np.flatnonzero(array1 != array2)
print(res)
# array([2], dtype=int64)
You can use numpy's where function to do this
array3 = np.where((array1-array2) != 0)
This is a non-numpy solution. You can use enumerate() with zip():
array1 = [1,2,3]
array2 = [1,2,4]
print([i for i, (x, y) in enumerate(zip(array1, array2)) if x != y])
# [2]
To find index of n changing elements between two lists we can use
c = set(a) - set(b)
[a.index(i) for i in c]
index call) per mismatching element.list(set(a1)-set(a2)) gives the list of all the elements which are not present in the set a2
a1 = [1,2,3]
a2 = [1,2,4]
arr=list(set(a1)-set(a2)) #arr=[3]
print(a1.index(arr[0])) #2
