Wrapping a loop in another loop in Python?

Question

Objective:

If the user types "right" the first two times, the smiley becomes sad as it can't get out of the forest.
If the user types "right" 3rd, 4th, 5th time an so on, the smiley becomes frustrated, chops some trees, makes a table and flips it over.
If the user types anything else, a message showing "Invalid input" is shown to the user and asked to give input again.
If the user types "left", the smiley gets out of the forest and the program terminates.

Python code:

n = input("You are in the Lost Forest\n****************\n****************\n :)\n****************\n****************\nGo left or right? ")
i = 1
while (n.lower() == "right"):
    if i < 3:    
        n = input("You are in the Lost Forest\n****************\n****************\n :(\n****************\n****************\nGo left or right? ")
    elif i >= 3:
        n = input("You are in the Lost Forest\n****************\n******       ***\n  (╯°□°）╯︵ ┻━┻\n****************\n****************\nGo left or right? ")
    i = i + 1    
while (n.lower() != "right") and (n.lower() != "left"):
    n = input("Invalid Input\nYou are in the Lost Forest\n****************\n****************\n :(\n****************\n****************\nGo left or right? ")    
while (n.lower() == "left"):
    print("\nYou got out of the Lost Forest!\n\o/")
    break

Bug:

If the user types anything other than "right" or "left" for the first two times and then types "right", the program immediately terminates without giving chance to type "left".

How should I edit my code?

you probably want to wrap your entire code with a loop that returns back to the top (first while loop, that is). That loop can for example have a while(playing==True): and before the break on your last loop, set playing=False — Tacratis
– Tacratis, Commented Feb 13, 2019 at 2:51
@AlexYu I tried changing my entire code to if - else format, but still unsuccessful. — Simba
– Simba, Commented Feb 13, 2019 at 2:59
I suppose you need to wrap everything into while True loop as @Tacratis suggests — Alex Yu
– Alex Yu, Commented Feb 13, 2019 at 3:02

Simba · Accepted Answer · 2019-02-13 12:35:09Z

1

More like this:

lost = "You are in the Lost Forest\n****************\n****************\n :(\n****************\n****************\nGo left or right? "
inp = lost
rightCount = 0
while True:
    n = input(inp)
    if (n.lower() == "right"):
        rightCount = rightCount + 1
        if rightCount > 3:
            inp = ("You are in the Lost Forest\n****************\n******       ***\n  (╯°□°）╯︵ ┻━┻\n****************\n****************\nGo left or right? ")
        else:
           inp = lost  
    elif n.lower() == "left":
        print("\nYou got out of the Lost Forest!\n\o/")    #syntax error fixed
        break
    else:
        inp = ("Invalid Input\nYou are in the Lost Forest\n****************\n****************\n :(\n****************\n****************\nGo left or right? ")

edited Feb 13, 2019 at 12:35

Simba

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answered Feb 13, 2019 at 3:50

see sharper

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Comments

Alex Yu · Accepted Answer · 2019-02-13 03:26:22Z

0

I suppose that you forgot to wrap everything into while True loop (or other kind of endless loop).

Is it what you need?

while True:
    n = input("You are in the Lost Forest\n****************\n****************\n :)\n****************\n****************\nGo left or right? ")
    i = 1
    if (n.lower() == "right"):
        if i < 3:    
            n = input("You are in the Lost Forest\n****************\n****************\n :(\n****************\n****************\nGo left or right? ")
        elif i >= 3:
            n = input("You are in the Lost Forest\n****************\n******       ***\n  (╯°□°）╯︵ ┻━┻\n****************\n****************\nGo left or right? ")
        i = i + 1    
    if (n.lower() != "right") and (n.lower() != "left"):
        n = input("Invalid Input\nYou are in the Lost Forest\n****************\n****************\n :(\n****************\n****************\nGo left or right? ")    
    if (n.lower() == "left"):
        print("\nYou got out of the Lost Forest!\n\o/")
        break

answered Feb 13, 2019 at 3:26

Alex Yu

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2 Comments

Simba Over a year ago

There are some bugs in your code. If I type "car" first time, it says "Invalid Input" but if I type "car" second time it doesn't say "Invalid Input". One more bug, even after typing "right" more than two times, the smiley never flips the table, it only shows a sad face.

Alex Yu Over a year ago

Those are your bugs in your code. I did not try solve all your needs, I solved only what you marked as a problem - what is below "Bug:" in your question

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