0

I currently have a try/catch around a line of code but when it errors out It's not properly printing out the error. Currently:

try
{
    // code here
}
catch (\Exception $e)
{
    return Redirect::back()
              ->withErrors($e->getResponse()->getBody()->getContents()["message"]);
}

prints:

{

Now if I use:

return Redirect::back()->withErrors($e->getResponse()->getBody()->getContents());

then I get:

{ "message":user doesn't exist }

How can I change this to, upon error, only print "user doesn't exist"?

3
  • What is var_dump($e->getResponse()->getBody()->getContents()); giving you? Commented Feb 21, 2019 at 16:47
  • """ {\n "message": "User doesn't exist."\n }\n """ Commented Feb 21, 2019 at 16:51
  • That's a json string. To get the message, you need to decode the string using json_decode() Commented Feb 21, 2019 at 16:52

2 Answers 2

3

You need to decode the json string so you can access the message attribute.

try {
    //code here
} catch (\Exception $e) {
    $response = json_decode($e->getResponse()->getBody()->getContents());
    $message = $response->message;

    return Redirect::back()->withErrors($message);
}
Sign up to request clarification or add additional context in comments.

Comments

1

You are trying to access a serialized JSON string with array access. This will obviously fail. Here a 1:1 solution which includes the JSON decoding.

try
{
    // code here
}
catch (\Exception $e)
{
    return (json_decode(Redirect::back()
              ->withErrors($e->getResponse()->getBody()->getContents()))->message;
}

Comments

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.