I want to Print Pointer Array value in Reverse
#include <stdio.h>
#define size 5
int main()
{
int a[size] = {1,2,3,4,5};
int i;
int *pa = a;
for(i = size; i >0; i--)
{
printf("a[%d] = %d\n",i,*pa);
pa++;
}
return 0;
}
Output:
a[5] = 1
a[4] = 2
a[3] = 3
a[2] = 4
a[1] = 5
The output I want is:
a[5] = 5
a[4] = 4
a[3] = 3
a[2] = 2
a[1] = 1
replace with this
#include <stdio.h>
#define size 5
int main()
{
int a[size] = {1,2,3,4,5};
int i;
int *pa = (a+size-1);
for(i = size; i >0; i--)
{
printf("a[%d] = %d\n",i,*pa);
pa--;
}
return 0;
}
You're making this too hard. Given a pointer into an array, you can use the indexing operator on it just as you would on the array itself:
int a[size] = {1,2,3,4,5};
int i;
int *pa = a;
for (i = size - 1; i >= 0; i--) {
printf("a[%d] = %d\n", i, pa[i]);
}
Alternatively, if you want to avoid the indexing operator for some reason, then just start your pointer at one past the end ...
*pa = a + size;
... and decrement it as you proceed through the loop:
for (i = size - 1; i >= 0; i--) {
pa--;
printf("a[%d] = %d\n", i, *pa);
}
Do note, by the way, that array indexing in C starts at 0, as the example codes above properly account for.
You don't have to use pointer. A simpler implementation
#include <stdio.h>
#define size 5
int main()
{
int a[size] = {1,2,3,4,5};
for(int i = size-1; i >=0; i--)
printf("a[%d] = %d\n",i,a[i]);
return 0;
}
