How to replace part of an array based on another part of the array?

Question

my question is how do I scan "my_list" for "comp" and change the associated time value from 200 to "t" only if 200 is less than t?

t = 3000
comp = 'C1'
my_list = [[200, 'C1'],[4000, 'C2']]

Output:

my_list = [[3000, 'C1'],[4000, 'C2']]

The opposite could be done with this scenario as the list shouldn't change as "t" is less than "5000":

t = 3000
comp = 'C1'
my_list = [[5000, 'C1'],[4000, 'C2']]

you may consider accepting an answer that helped you understand and solve your problem! meta.stackexchange.com/questions/5234/… — DirtyBit
– DirtyBit, Commented Mar 8, 2019 at 15:32

Arkistarvh Kltzuonstev · Accepted Answer · 2019-03-07 13:17:15Z

1

Try this:

my_list = [[t,k[1]] if( k[1]==comp and k[0]<t ) else k for k in my_list]

edited Mar 7, 2019 at 13:17

answered Mar 7, 2019 at 13:08

Arkistarvh Kltzuonstev

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1 Comment

DirtyBit Over a year ago

It would fail for: my_list = [[200, 'C3'],[4000, 'C2']]

DirtyBit · Accepted Answer · 2019-03-07 13:18:12Z

0

Using deepcopy:

t = 3000
comp = 'C1'
my_list = [[200, 'C1'],[4000, 'C2']]

for e in my_list[:]:
    if comp in e:
        if e[0] < t:
            e[0] = t

print(my_list)

Eventually, one-liner:

print([[t,e[1]] if e[1] == comp and e[0]<t else e for e in my_list])

OUTPUT:

[[3000, 'C1'], [4000, 'C2']]

edited Mar 7, 2019 at 13:18

answered Mar 7, 2019 at 13:08

DirtyBit

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